16a^2-25^2=0

Solution for 16a^2-25^2=0 equation:

16a^2-25^2=0

We add all the numbers together, and all the variables

16a^2-625=0

a = 16; b = 0; c = -625;
Δ = b2-4ac
Δ = 02-4·16·(-625)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*16}=\frac{-200}{32}
=-6+1/4
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*16}=\frac{200}{32}
=6+1/4
$